If the rain drop doesn't hit the bullet, then how do you explain the "clean" bullet hole? All the others have a black ring and that one doesn't....just a hole in the paper far away from the group.
As for the supersonic pressure wave, if anything deforms it, would not the resultant shock be passed back to the projectile and thus affect it?
* doghunter *
As I wrote earlier, the probability of your bullet striking a rain drop is fairly slim. That statement is not of my own thoughts, but rather the result of some fairly exhaustive mathematics. If you shoot enough in the rain you're gonna hit a rain drop and the result is not likeable.
I'll say this and quit writing (yeah, really Wilbur), the probability of your bullet hitting a rain drop is fairly slim even in a moderate rain, but there is nothing physical involved - just the bullet being in the same place as a rain drop at the same time.
A common misconception. Air, water, whatever, flows through the Mach wave, which is just a transition in fluid properties, including pressure and density.
Even air does not flow over a Mach wave.
The Bernoulli equation fails since it assumes a standing pressure wave cannot exist.
From Wikpedia: "Shock waves can travel through any medium, including solids, liquids, gasses, and plasmas."
https://en.wikipedia.org/wiki/Shock_wave
Mach waves are cone-shaped, and extend outward from the bullet in all directions, including to the ground. If air couldn't flow through the wave, then the bullet would have to push an increasing mass of air along with it as it traveled from muzzle to target. It would be lucky to go a few feet before it accumulated so much resistance that it fell to the ground.
The same sort of Mach wave extends from a supersonic aircraft at 10,000 feet all the way to the ground. If planes had to push everything in its path in front of their Mach wave, they couldn't fly.
When we hear a sonic boom, the Mach wave has passed through our bodies. It does not push us to the ground.
The cloud of water vapor that many of us have seen when a bullet strikes a raindrop is not pushed by the Mach wave past the target. The Mach wave passes through it.
Enough examples?
Cheers,
Keith
No need to bring Bernoulli into this.
Added:
Here is a better reference for the mathematically-inclined: https://en.wikipedia.org/wiki/Rankine–Hugoniot_conditions
u2 in the first three equations (conservation of mass, momentum and energy) is the speed of air passing through the shock wave. u2 is not zero.
When flow is choked, it has reached a maximum that cannot be exceeded without changing the upstream conditions. The flow does not suddenly stop.
https://en.wikipedia.org/wiki/Choked_flow
The second equation gives the mass flow rate through the shock wave under choked conditions.
Again fluids, including air, flow through a shock wave, whether it is around a bullet or in a venturi.