Richard & Gene
Let me quote directly from William McDonald and Ted Almgren, ballisticians at Sierra Bullets:
". . . in the case of a headwind acting alone and blowing from the target toward the shooter, the speed of the bullet relative to the air would be greater than it would be if the air were still. Then, the drag on the bullet would be higher, and the bullet would travel slower relative to the ground and drop more than it would if the air were still. On the other hand, for a tailwind acting alone and blowing from the shooter toward the target, the speed of the bullet relative to the air would be less than it would be if the air were still. Then, the drag on the bullet would be lower, and the bullet would travel faster relative to the ground and drop less than it would if the air were still. . ."
Calculating the effect of head and tail winds is basic high school math. Not a lot of room for misconceptions.
What am I missing???
Or, maybe a better question would be, what are McDonald & Almgren missing?
Ray
Ray,
Knowing there will be a hue and cry of momentous proportions,
the above statement by McDonald & Almgren is incorrect!
From an observer on the ground standpoint it is true that the speed of the bullet relative to the air is greater when a headwind is blowing. But the drag on the bullet has nothing to do with what someone (or an instrument) on the ground observes.
Drag force on the bullet is only generated by the air velocity as seen by the bullet. Since the bullet is not connected to the ground it does not feel a headwind.
You observe the effects of the headwind by measuring bullet speed relative to the fixed ground. If you want the actual bullet speed relative to the air around it you must subtract the value of the headwind.
Actual bullet speed in the air surrounding it determines the drag force on the bullet.What Lisa gave you was a way of looking at headwinds as a drag producer but it will not work to compute the actual drag forces acting on the bullet, unless you subtract out the value of the headwind.
As I stated before:
Drag Force (acting to decelerate the bullet) =
1/2 *(wind velocity measured at the bullet not the ground)^2 * air density
*drag coefficient (mainly a function of shape).
What Lisa gave you was a layman's way of explaining the effect of a headwind, not the actual calculation methods for drag.
I stand by my statement that your saying that a headwind causes an increase in drag is incorrect.
Headwind causes an increase in the time it takes the bullet to reach the target, and therefore it drops more due to gravity. The drag force on the bullet has nothing to do with the headwind.
Richard